Đáp án:
`(2 : x -` `\frac{1}{3}``)` `.(` $x^{3}$ `- 8)` `= 0`
⇔ \(\left[ \begin{array}{l}2:x -\frac{1}{3} = 0\\x^{3}-8=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}2:x = 0+\frac{1}{3}\\x^{3}=0+8\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}2:x = \frac{1}{3}\\x^{3}=8\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x = 2:\frac{1}{3}\\x^{3}=2^{3} \end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x = 6\\x=3 \end{array} \right.\)
Vậy `x = 2` hoặc `x = 6`
