Kẻ $Aa$ về phía bên trái sao cho $Aa//Hx//Ky$
$Aa//Hx$
$→\widehat{H}=\widehat{HAa}=20^\circ$ (so le trong)
$→\widehat{KAa}=50^\circ-20^\circ=30^\circ$
$Aa//Ky$
$→\widehat{AKy}=\widehat{KAa}$ (so le trong)
mà $\widehat{KAa}=30^\circ$
$→\widehat{AKy}=30^\circ$
Vậy $\widehat{AKy}=30^\circ$