Đáp án:
\({d_{A/{H_2}}} = 8,5\)
Giải thích các bước giải:
Ta có:
\({m_{{O_2}}} = 1.32 = 32{\text{ gam}}\)
\({m_{{H_2}}} = 1.2 = 2{\text{ gam}}\)
\( \to {m_A} = {m_{{O_2}}} + {m_{{H_2}}} = 34{\text{ gam}}\)
\({n_A} = {n_{{H_2}}} + {n_{{O_2}}} = 2{\text{ mol}}\)
\( \to \overline {{M_A}} = \frac{{{m_A}}}{{{n_A}}} = \frac{{34}}{2} = 17(u)\)
\( \to {d_{A/{H_2}}} = \frac{{{M_A}}}{{{M_{{H_2}}}}} = \frac{{17}}{2} = 8,5\)