Đáp án:
\(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=-1\end{array} \right.\)
Giải thích các bước giải:
$5x^2.(2x-3)+(2x^2+3x+3).(3-2x)=6x^3-9x^2$
$⇔5x^2.(2x-3)-(2x^2+3x+3).(2x-3)-3x^2.(2x-3)=0$
$⇔(2x-3).(5x^2-2x^2-3x-3-3x^2)=0$
$⇔(2x-3).(-3x-3)=0$
$⇔\(\left[ \begin{array}{l}2x-3=0\\-3x-3=0\end{array} \right.\)$
$⇔\(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=-1\end{array} \right.\)$
