ĐK: $x\ne \dfrac{\pi}{2}+k\pi$
Chia 2 vế cho $\cos^3x$:
$\dfrac{\tan x}{\cos^2x}+\dfrac{1}{\cos^2x}-4\tan^3x=0$
$\Leftrightarrow \tan x(1+\tan^2x)+1+\tan^2x-4\tan^3x=0$
$\Leftrightarrow -4\tan^3x+2\tan^2x+\tan x+1=0$
$\Leftrightarrow \tan x-1=0$ (*)
$\to B$ (chia 2 vế đáp án B cho $\cos x$ ta được (*))