Giải thích các bước giải:
\(\begin{array}{l}
a)Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
{n_{Mg}} = 0,3mol\\
{m_{{H_2}S{O_4}}} = \dfrac{{550 \times 7\% }}{{100\% }} = 38,5g\\
\to {n_{{H_2}S{O_4}}} = 0,39mol\\
\to {n_{{H_2}S{O_4}}} > {n_{Mg}} \to {n_{{H_2}S{O_4}}}dư\\
b)\\
{n_{MgS{O_4}}} = {n_{Mg}} = 0,3mol \to {m_{MgS{O_4}}} = 36g\\
c)\\
{n_{{H_2}S{O_4}(pt)}} = {n_{Mg}} = 0,3mol\\
\to {n_{{H_2}S{O_4}(dư)}} = 0,09mol \to {m_{{H_2}S{O_4}(dư)}} = 8,82g\\
d)\\
{n_{{H_2}}} = {n_{Mg}} = 0,3mol \to {V_{{H_2}}} = 6,72l
\end{array}\)