Đáp án:
\(\begin{array}{l} b,\ C_{M_{\text{dd H$_2$SO$_4$}}}=0,6\ M.\\ c,\ C_{M_{Al_2(SO_4)_3}}=0,2\ M.\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a,\\ PTHH:Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ b,\\ n_{Al_2O_3}=\dfrac{10,2}{102}=0,1\ mol.\\ Theo\ pt:\ n_{H_2SO_4}=3n_{Al_2O_3}=0,3\ mol.\\ \Rightarrow C_{M_{\text{dd H$_2$SO$_4$}}}=\dfrac{0,3}{0,5}=0,6\ M.\\ c,\\ Theo\ pt:\ n_{Al_2(SO_4)_3}=n_{Al_2O_3}=0,1\ mol.\\ V_{\text{dd spư}}=V_{\text{dd tpư}}=50\ ml=0,5\ lít.\\ \Rightarrow C_{M_{Al_2(SO_4)_3}}=\dfrac{0,1}{0,5}=0,2\ M.\end{array}\)
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