Ta có : y=(x)=3$x^{2}$ -1
Nếu f(-2)⇒ y=3.$(-2)^{2}$ -1=-13
Nếu f($\frac{1}{2}$ )⇒y=3.($\frac{1}{2}$)^2-1=3.$\frac{1}{4}$-1=$\frac{3}{4}$ -1=$\frac{-1}{4}$
Nếu f($\frac{-2}{√3}$ )⇒y=3.($\frac{-2}{√3}$ )-1=(-2) -1=-3
Nếu f=(a+1)⇒y=3.(a+1)-1? ( xin lỗi mik ko bt lm ạ)
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