Đáp án:
Giải thích các bước giải:
`(x-5)^2016=(x-5)^2018`
`=>(x-5)^2018-(x-5)^2016=0`
`=>(x-5)^2.(x-5)^2016-(x-5)^2016=0`
`=>(x-5)^2016[(x-5)^2-1]=0`
`=>`\(\left[ \begin{array}{l}(x-5)^{2016}=0\\(x-5)^2=1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x-5=0\\ \left[ \begin{array}{l}x-5=1\\x-5=-1\end{array} \right. \end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=5\\ \left[ \begin{array}{l}x=6\\x=4\end{array} \right. \end{array} \right.\)
Vậy `x in{4;5;6}`
