Đáp án:
$\begin{array}{l}
{\left( {\sqrt[n]{a}} \right)^m} = {\left( {{a^{\dfrac{1}{n}}}} \right)^m} = {a^{\dfrac{1}{n}.m}} = {a^{\dfrac{m}{n}}}\\
\sqrt[n]{{{a^m}}} = {\left( {{a^m}} \right)^{\dfrac{1}{n}}} = {a^{m.\dfrac{1}{n}}} = {a^{\dfrac{m}{n}}}\\
\Rightarrow {\left( {\sqrt[n]{a}} \right)^m} = \sqrt[n]{{{a^m}}}
\end{array}$