Đáp án+giải thích các bước giải:
`3/(2x^2+2x)+(2x-1)/(x^2-1)-2/x`
$=\dfrac{3}{2x(x+1)}+\dfrac{2x-1}{(x-1)(x+1)}-\dfrac{2}{x}$
$=\dfrac{3(x-1)}{2x(x-1)(x+1)}+\dfrac{(2x-1).2x}{2x(x-1)(x+1)}-\dfrac{2.2(x-1)(x+1)}{2x(x-1)(x+1)}$
$=\dfrac{3x-3+4x^2-2x-4x^2+4}{2x(x-1)(x+1)}$
$=\dfrac{x+1}{2x(x-1)(x+1)}$
$=\dfrac{1}{2x(x-1)}$