Đáp án:
$\text{Vậy x∈{$\dfrac{6}{5};\dfrac{2}{5}$}}$
Giải thích các bước giải:
$|x-\dfrac{4}{5}|=\dfrac{2}{5}$
$<=>$\(\left[ \begin{array}{l}x-\dfrac{4}{5}=\dfrac{2}{5}\\x-\dfrac{4}{5}=-\dfrac{2}{5}\end{array} \right.\)
$<=>$\(\left[ \begin{array}{l}x=\dfrac{2}{5}+\dfrac{4}{5}\\x=-\dfrac{2}{5}+\dfrac{4}{5}\end{array} \right.\)
$<=>$\(\left[ \begin{array}{l}x=\dfrac{6}{5}\\x=\dfrac{2}{5}\end{array} \right.\)
$\text{Vậy x∈{$\dfrac{6}{5};\dfrac{2}{5}$}}$