Đáp án:
._.
Giải thích các bước giải:
`a) n+2 in Ư(-16)`
`=> n+2 in {-16;-8;-2;-1;1;2;8;16}`
`=> n in {-18;-10;-4;-3;-1;0;6;14}`
`b) 2n+8 in B(n+1)`
`=> n+1 vdots 2n+8`
`=> 2n+2 vdots 2n+8`
`=> 2n+8-6 vdots 2n+8`
Mà `2n+8 vdots 2n+8`
`=> 6 vdots 2n+8`
`=> 2n+8 in Ư(6)={-6;-3;-2;-1;1;2;3;6}`
Mà `2n+8` lẻ
`=> 2n+8 in {-6;-2;2;6}`
`=> 2n in {-14;-10;-6;-2}`
`=> n in {-7;-5;-3;-1}`
`c) 3n-1 vdots n-2`
`=> 3(n-2)+5 vdots n-2`
Mà `3(n-2) vdots n-2`
`=> 5 vdots n-2`
`=> n-2 in Ư(5)={-5;-1;1;5}`
`=> n in {-3;1;3;7}`
`d) n^2+2 in B(n^2+1)`
`=> n^2+1 vdots n^2+2`
`=> n^2+2-1 vdots n^2+2`
Mà `n^2+2 vdots n^2+2`
`=> 1 vdots n^2+2`
`=> n^2+2 in Ư(1)={-1;1}`
`=> n^2 in {-3;-1}`
`=>` Không có `n` thỏa mãn
