Đáp án:
$P=10$
Giải thích các bước giải:
$P^2=b(a-c)-c(a-b)$
$P^2=ab-bc-ac+bc$
$P^2=ab-ac=a(b-c)$
$P^2=(-20).(-5)$
$P^2=100$
Vậy $P=10$
Xin hay nhất ạ T_T
Ta có:
P² = b ( a - c ) - c ( a - b )
= ba - bc - ca + cb
= ( ba - ca ) - ( bc - cb )
= ba - ca
=> P² = a ( b - c )
= ( -20 ) . ( - 5 )
= 100
=> P = √100
=> P = 10
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