b/ $\dfrac{-2}{5}:\dfrac{4}{25}+\dfrac{2}{7}\cdot\dfrac{3}{4}$
$=\dfrac{-2}{5}\cdot\dfrac{25}{4}+\dfrac{2.3}{7.4}$
$=\dfrac{-5}{2}+\dfrac{3}{14}$
$=\dfrac{-5.7}{2.7}+\dfrac{3}{14}$
$=\dfrac{-35}{14}+\dfrac{3}{14}$
$=\dfrac{-32}{14}$
$=\dfrac{-16}{7}$
Vậy $\dfrac{-2}{5}:\dfrac{4}{25}+\dfrac{2}{7}\cdot\dfrac{3}{4}=\dfrac{-16}{7}$.