Đáp án:
$\displaystyle\int\limits_1^2(2x-1)^4dx =\dfrac{121}{5}$
Giải thích các bước giải:
$\quad \displaystyle\int\limits_1^2(2x-1)^4dx$
$= \dfrac12\displaystyle\int\limits_1^2(2x-1)^4d(2x-1)$
$= \dfrac12\cdot\dfrac{(2x-1)^5}{5}\Bigg|_1^2$
$=\dfrac{3^5 - 1}{10}$
$= \dfrac{121}{5}$