\(2xy-2x+y=6\\↔2x(y-1)+y-1-5=0\\↔(2x+1)(y-1)=5\\→(2x+1);(y-1)∈Ư(5)=\{±1;±5\}\\→Ta\,\, co\,\, bang\,\,:\begin{array}{|c|c|c|}\hline2x+1&1&5&-1&-5\\\hline y-1&5&1&-5&-1\\\hline x&0&2&-1&-3\\\hline y&6&2&-4&0\\\hline\end{array}\) mà pt có nghiệm nguyên dương \(→(x;y)=\{(0;6);(2;2)\}\)
