$Al_4C_3+12H_2O\to 4Al(OH)_3+3CH_4$
$2CH_4\xrightarrow{{1500^oC}} C_2H_2+3H_2$
$3C_2H_2\xrightarrow{{600^oC, C}} C_6H_6$ (benzen)
$2CH\equiv CH\xrightarrow{{CuCl, NH_4Cl, t^o}} CH_2=CH-C\equiv CH$
$CH\equiv C-CH=CH_2+H_2\xrightarrow{{Pd/PbCO_3, t^o}} CH_2=CH-CH=CH_2$
$nCH_2=CH-CH=CH_2\xrightarrow{{t^o, p, xt}} (CH_2-CH=CH-CH_2)_n$ (cao su Buna)