Tìm \(x\) , biết
a. \(\frac{2}{3} + \frac{5}{3}x = \frac{5}{7}\)
b. \(\sqrt {1,69} .\left( {2\sqrt x + \sqrt {\frac{{81}}{{121}}} } \right) = \frac{{13}}{{10}}\)
c. \(\frac{{x - 5}}{4} = \frac{{1 - 2x}}{7}\)
d. \(\left| {\frac{3}{5}\sqrt x - \frac{1}{{20}}} \right| - \frac{3}{4} = \frac{1}{5}\)
A.a) \(x = \frac{1}{{5}}\)
b) \(x = \frac{{13 }}{5}\)
c) \(x = \frac{1}{{12}}\)
d) \(x = \frac{{29}}{5}\)
B.a) \(x = \frac{1}{{53}}\)
b) \(x = \frac{{5 }}{13}\)
c) \(x = \frac{1}{{21}}\)
d) \(x = \frac{{2}}{59}\)
C.a) \(x = \frac{1}{{35}}\)
b) \(x = \frac{{13 }}{5}\)
c) \(x = \frac{1}{{121}}\)
d) \(x = \frac{{25}}{9}\)
D.a) \(x = \frac{1}{{3}}\)
b) \(x = \frac{{35 }}{5}\)
c) \(x = \frac{12}{{121}}\)
d) \(x = \frac{{5}}{9}\)
a. \(\frac{2}{3} + \frac{5}{3}x = \frac{5}{7}\)
b. \(\sqrt {1,69} .\left( {2\sqrt x + \sqrt {\frac{{81}}{{121}}} } \right) = \frac{{13}}{{10}}\)
c. \(\frac{{x - 5}}{4} = \frac{{1 - 2x}}{7}\)
d. \(\left| {\frac{3}{5}\sqrt x - \frac{1}{{20}}} \right| - \frac{3}{4} = \frac{1}{5}\)
A.a) \(x = \frac{1}{{5}}\)
b) \(x = \frac{{13 }}{5}\)
c) \(x = \frac{1}{{12}}\)
d) \(x = \frac{{29}}{5}\)
B.a) \(x = \frac{1}{{53}}\)
b) \(x = \frac{{5 }}{13}\)
c) \(x = \frac{1}{{21}}\)
d) \(x = \frac{{2}}{59}\)
C.a) \(x = \frac{1}{{35}}\)
b) \(x = \frac{{13 }}{5}\)
c) \(x = \frac{1}{{121}}\)
d) \(x = \frac{{25}}{9}\)
D.a) \(x = \frac{1}{{3}}\)
b) \(x = \frac{{35 }}{5}\)
c) \(x = \frac{12}{{121}}\)
d) \(x = \frac{{5}}{9}\)
Loga
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