Giải thích các bước giải:
Ta có $AB\cap CD=O$
$\to \widehat{AOD}=\widehat{COB},\widehat{AOC}=\widehat{DOB}$ (đối đỉnh)
Ta có: $\widehat{AOC}-\widehat{AOD}=20^o\to \widehat{AOC}=\widehat{AOD}+20^o$
$\widehat{AOC}+\widehat{AOD}=\widehat{DOC}=180^o$
$\to \widehat{AOD}+20^o+\widehat{AOD}=180^o$
$\to 2\widehat{AOD}+20^o=180^o$
$\to \widehat{AOD}=80^o$
$\to \widehat{AOC}=100^o$
$\to \widehat{AOD}=\widehat{COB}=80^o,\widehat{AOC}=\widehat{DOB}=100^o$