`a) f(1/2)=2.``\frac{1}{2}-1=0`
`g(4)=3.`$\sqrt{4}-2=3.2-2=4$
`b)f(a)=g(a)`
`⇔2a-1=3`$\sqrt{a}-2$
`⇔2a-1-3`$\sqrt{a}+2=0$
`⇔2a-3`$\sqrt{a}1=0$
`⇔2a-2`$\sqrt{a}-$$\sqrt{a}+1=0$
`⇔2`$\sqrt{a}($$\sqrt{a}-1)-($$\sqrt{a}-1)=0$
`⇔(2`$\sqrt{a}-1)($$\sqrt{a}-1)=0$
`⇔`\(\left[ \begin{array}{l}2\sqrt{a}-1=0\\\sqrt{a}-1=0\end{array} \right.\) `⇔`\(\left[ \begin{array}{l}a=\frac{1}{4}\\a=1\end{array} \right.\)
`c)` khó quá nên mình chưa nghĩ ra :<
`#Pape`
