Đáp án:
a) 0,5M
b) 0,14M
c) 1,15 ml
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O\\
{n_{NaOH}} = 0,1 \times 0,2 = 0,02\,mol\\
{n_{C{H_3}COOH}} = {n_{NaOH}} = 0,02\,mol\\
{C_M}C{H_3}COOH = \dfrac{{0,02}}{{0,04}} = 0,5M\\
b)\\
{V_{{\rm{dd}}spu}} = 0,04 + 0,1 = 0,14\,l\\
{n_{C{H_3}COONa}} = {n_{C{H_3}COOH}} = 0,02\\
{C_M}C{H_3}COONa = \dfrac{{0,02}}{{0,14}} \approx 0,14M\\
c)\\
{C_2}{H_5}OH + {O_2} \to C{H_3}COOH + {H_2}O\\
{n_{{C_2}{H_5}OH}} = {n_{C{H_3}COOH}} = 0,02\,mol\\
{m_{{C_2}{H_5}OH}} = 0,02 \times 46 = 0,92g\\
{V_{{C_2}{H_5}OH}} = \dfrac{{0,92}}{{0,8}} = 1,15\,ml
\end{array}\)