Đáp án:
\({m_{{C_2}{H_5}OH}} = 46{\text{ gam}}\)
\( {m_{{C_6}{H_{12}}{O_6}}} = 100{\text{ gam}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({C_6}{H_{12}}{O_6}\xrightarrow{{men,90\% }}2{C_2}{H_5}OH + 2C{O_2}\)
Ta có:
\({n_{C{O_2}}} = \frac{{22,4}}{{22,4}} = 1{\text{ mol = }}{{\text{n}}_{{C_2}{H_5}OH}}\)
\( \to {m_{{C_2}{H_5}OH}} = 1.46 = 46{\text{ gam}}\)
Ta có:
\({n_{{C_6}{H_{12}}{O_6}{\text{ lt}}}} = \frac{1}{2}{n_{C{O_2}}} = 0,5{\text{ mol}}\)
\( \to {n_{{C_6}{H_{12}}{O_6}}} = \frac{{0,5}}{{90\% }}\)
\( \to {m_{{C_6}{H_{12}}{O_6}}} = \frac{{0,5}}{{90\% }}.(12.6 + 12 + 16.6) = 100{\text{ gam}}\)
