`\sqrt(x^2-1)-\sqrt(3x^2+4x+1)=(8-2x)\sqrt(x+1)`
`⇔\sqrt((x-1)(x+1))-\sqrt(3(x+1/3)(x+1))-(8-2x)\sqrt(x+1)=0`
`⇔\sqrt(x+1)(\sqrt(x-1)-\sqrt(3(x+1/3))-8+2x)=0`
⇔\(\left[ \begin{array}{l}\sqrt(x+1)=0\\\sqrt(x-1)-3\sqrt(x+1/3)-8+2x=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x+1=0\\(x-5)(1/\sqrt((x-1)+2)+2-1/(\sqrt((x+1/3)+4)=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-1\\x-5=0(1/\sqrt((x-1)+2)+2-1/(\sqrt((x+1/3)+4>0)\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-1\\x=5\end{array} \right.\)
