Đáp án:
\({V_{dd{\text{ rượu}}}} =71,875{\text{ ml}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({C_6}{H_{12}}{O_6} + 6{O_2}\xrightarrow{{{t^o}}}6C{O_2} + 6{H_2}O\)
\({C_6}{H_{12}}{O_6}\xrightarrow{{men}}2{C_2}{H_5}OH + 2C{O_2}\)
Ta có:
\({n_{C{O_2}}} = \frac{{33,6}}{{22,4}} = 1,5{\text{ mol}}\)
\( \to {n_{{C_6}{H_{12}}{O_6}}} = \frac{1}{6}{n_{C{O_2}}} = 0,25{\text{ mol}}\)
\( \to {n_{{C_2}{H_5}OH}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 0,5{\text{ mol}}\)
\( \to {m_{{C_2}{H_5}OH}} = 0,5.46 = 23{\text{ gam}}\)
\( \to {n_{{C_2}{H_5}OH}} = \frac{{23}}{{0,8}} = 28,75{\text{ ml}}\)
\( \to {V_{dd{\text{ rượu}}}} = \frac{{28,75}}{{40\% }} = 71,875{\text{ ml}}\)
