Đáp án:
`d)sqrt{(sqrt3-3)^2}*\sqrt{1/(3-sqrt3)^2}`
`=\sqrt{(sqrt3-3)^2*1/(3-sqrt3)^2}`
`=sqrt{(3-sqrt3)^2*1/(3-sqrt3)^2}`
`=sqrt{1}=1`
`d)2sqrt3(sqrt2-1)+(1+sqrt3)^2-2sqrt6`
`=2sqrt{3}*sqrt2-2sqrt3*1+3+1+2sqrt3-2sqrt6`
`=4+2sqrt3-2sqrt3+2sqrt6-2sqrt6`
`=4`
`e)(sqrt{3-sqrt5}+sqrt{3+sqrt5})^2`
`=3-sqrt5+3+sqrt5+2\sqrt{(3-sqrt5)(3+sqrt5)}`
`=6-2\sqrt{9-5}`
`=6-2.sqrt4`
`=6-2.2=6-4=2`.
