Đáp án+bước giải:
a,$\frac{9}{17}$×$\frac{6}{11}$×$\frac{52}{3}$×121×$\frac{5}{22}$
=($\frac{9}{17}$×$\frac{52}{3}$)×($\frac{6}{11}$×121)×$\frac{5}{22}$
=$\frac{156}{17}$×(66×$\frac{5}{22}$ )
=$\frac{156}{17}$×15
=$\frac{2304}{17}$
b,3$\frac{2}{15}$×$\frac{2}{9}$×2$\frac{16}{19}$÷9$\frac{2}{5}$×9$\frac{1}{2}$÷$\frac{2}{3}$
=$\frac{47}{15}$×$\frac{2}{9}$×$\frac{54}{19}$÷$\frac{47}{5}$×$\frac{19}{2}$÷$\frac{2}{3}$
=$\frac{47}{15}$×$\frac{2}{9}$×$\frac{54}{19}$×$\frac{5}{47}$×$\frac{19}{2}$×$\frac{3}{2}$
=($\frac{47}{15}$×$\frac{5}{47}$)×($\frac{2}{9}$×$\frac{3}{2}$)×($\frac{54}{19}$×$\frac{19}{2}$)
=$\frac{1}{5}$×$\frac{1}{3}$×27
=$\frac{9}{5}$
