Fe+2HCl→FeCl2+H2
Fe2O3+6HCl→2FeCl3+3H2O
nH2=2,24/22,4=0,1mol
→nFe=0,1mol
mFe=0,5.56=5,6g
mFe2O3=21,6-5,6=16g
%mFe=5,6/21,6.100%=25,93%
%mFe2O3=100-25,93=74,07%
nFe2O3=16/160=0,1mol
nHCl=0,1.2+0,1.6=0,8mol
Vdd HCl=0,8/1=0,8l
nFeCl2=0,1mol
CM FeCl2=0,1/0,8=0,125M
nFeCl3=0,1.2=0,2mol
CM FeCl3=0,2/0,8=0,25M
