Đáp án:
`2+(x+1)/(sqrtx)=9/2`
`<=>` `(x+1)/sqrtx=5/2`
`<=>` `2(x+1)=5sqrtx`
`<=>` `5sqrtx=2x+2`
`<=>` `25x=(2x+2)^2`
`<=>` `25x=4x^2+8x+4`
`<=>` `25x-4x^2-8x-4=0`
`<=>` `17x-4x^2-4=0`
`<=>` `4x^2-17+4=0`
`<=>` `4x^2-x-16x+4=0`
`<=>` `x(4x-1)-4(4x-1)=0`
`<=>` `(x-4)(4x-1)=0`
`<=>` \(\left[ \begin{array}{l}x-4=0\\4x-1=0\end{array} \right.\) `<=>` \(\left[ \begin{array}{l}x=4\\x=\dfrac{1}{4}\end{array} \right.\)$(t/m)$
Vậy phương trình có nghiệm `S={4;1/4}`
