$\sqrt{x - 4}$ `= 4 - x`
`Do` $\sqrt{x - 4}$ `≥ 0`
`⇒ x ≥ 4 (1)`
`Mà` $\sqrt{x - 4}$ `= 4 - x`
`⇒ 4 - x ≥ 0`
`⇒ x ≤ 4 (2)`
`Từ (1) và (2)`
`⇒ x = 4`
`Thử lại :`
`text(x = 4 thỏa mãn phương trình)`
`Vậy S = {4}`
Đáp án:
Giải thích các bước giải:
`\sqrt{x-4}=4-x`
ĐK:
\(\begin{cases} x-4 \ge 0\\ 4-x \ge 0\end{cases}\)
`⇔` \(\begin{cases} x \ge 4\\ x \le 4\end{cases}\)
`⇒ x=4`
Thay lại `x=4` vào PT ta có:`\sqrt{4-4}=4-4`
`⇔ 0=0` (đúng)
Vậy `S={4}`
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