`#AkaShi`
PTHH:
`CuO + 2HCl -> CuCl_2 + H_2O`
`a)`
`→n_{CuO}=10/80=0,125 (mol)`
Theo tỉ lệ pt ta tính được:
`n_{HCl}=2xxn_{CuO}=0,125xx2=0,25 (mol)`
`→m_{HCl}=0,25xx36,5=9,125`
`→m_{dd\ HCl}=9,125:7,3%=125 (g)`
`b)`
`→n_{CuCl_2}=n_{CuO}=0,125 (mol)`
`→m_{CuCl_2}=0,125xx135=16,875 (g)`
`→m_{dd\ sau\ pư}=m_{CuO}+m_{HCl}=10+125=135 (g)`
`→C%_{CuCl_2}=(16,875)/135xx100%=12,5%`
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