Em tham khảo nha :
\(\begin{array}{l}
1)\\
a)\\
CaO + {H_2}O \to Ca{(OH)_2}\\
S{O_2} + {H_2}O \to {H_2}S{O_3}\\
C{O_2} + {H_2}O \to {H_2}C{O_3}\\
b)\\
S{O_2} + 2KOH \to {K_2}S{O_3} + {H_2}O\\
C{O_2} + 2KOH \to {K_2}C{O_3} + {H_2}O\\
c)\\
CaO + {H_2}S{O_4} \to CaS{O_4} + {H_2}O\\
d)\\
\text{Khí CO,NO được làm khô bằng CaO}\\
2)\\
S + {O_2} \to S{O_2}\\
S{O_2} + 2KOH \to {K_2}S{O_3} + {H_2}O\\
{K_2}S{O_3} + 2HCl \to 2KCl + S{O_2} + {H_2}O\\
S{O_2} + Ca{(OH)_2} \to CaS{O_3} + {H_2}O\\
CaS{O_3} + 2HCl \to CaC{l_2} + S{O_2} + {H_2}O
\end{array}\)
\(\begin{array}{l}
3)\\
{n_{S{O_2}}} = \dfrac{{4,49}}{{22,4}} = 0,2mol\\
Ca{(OH)_2} + S{O_2} \to CaS{O_3} + {H_2}O\\
{n_{Ca{{(OH)}_2}}} = {n_{S{O_2}}} = 0,2mol\\
{m_{Ca{{(OH)}_2}}} = 0,2 \times 74 = 14,8g\\
C{\% _{Ca{{(OH)}_2}}} = \dfrac{{14,8}}{{200}} \times 100\% = 7,4\% \\
b)\\
{n_{CaS{O_3}}} = {n_{S{O_2}}} = 0,2mol\\
{m_{CaS{O_3}}} = 0,2 \times 120 = 24g
\end{array}\)
