Em tham khảo nha:
\(\begin{array}{l}
A:F{e_3}{O_4}\\
F{e_3}{O_4} + 8HCl \to FeC{l_2} + 2FeC{l_3} + 4{H_2}O\\
D:FeC{l_2}\\
F:FeC{l_3}\\
F{e_3}{O_4} + 4CO \xrightarrow{t^0} 3Fe + 4C{O_2}\\
X:CO\\
F{e_3}{O_4} + 4{H_2} \xrightarrow{t^0} 3Fe + 4{H_2}O\\
Y:{H_2}\\
3F{e_3}{O_4} + 8Al \xrightarrow{t^0} 4A{l_2}{O_3} + 9Fe\\
Z:Al\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
B:HCl\\
2FeC{l_2} + C{l_2} \to 2FeC{l_3}\\
E:C{l_2}\\
FeC{l_3} + 3NaOH \to Fe{(OH)_3} + 3NaCl\\
G:NaOH\\
H:Fe{(OH)_3}\\
2Fe{(OH)_3} \xrightarrow{t^0} F{e_2}{O_3} + 3{H_2}O
\end{array}\)
