nCa(OH)2 = 0.5 mol
nCO2 = 0.25 mol
TH1 : Chỉ tạo ra CaCO3
Ca(OH)2 + CO2 --> CaCO3 + H2O
__________0.25_____0.25
VCO2 = 0.25 x 22.4 = 5.6 l
TH2 : Tạo ra 2 muối
Ca(OH)2 + CO2 --> CaCO3 + H2O
0.25______0.25_____0.25
Ca(OH)2 + 2CO2 --> Ca(HCO3)2
0.25___0.5
VCO2 = 0.75*22.4=16.8 (l)