Giả sử có 1 mol hh A phản ứng:
Phản ứng phân hủy amoniac:
$2N{H_3} \to {N_2} + 3{H_2}$
$z\,mol \to 0.5z \to 1.5z$
$1\,mol\,A\,\left\{ \begin{gathered} {N_2}\,x\,mol \hfill \\ {H_2}\,y\,mol \hfill \\ N{H_{3\,}}\,z\,mol \hfill \\ \end{gathered} \right.\xrightarrow{{{t^o}}}125\% \times 1mol = 1.25\,mol\,B\left\{ \begin{gathered} {N_2}:x + 0.5z \hfill \\ {H_2}:1.5z + y \hfill \\ \end{gathered} \right.\xrightarrow{{CuO,\,loai\,nuoc}}25\% \times 1.25mol = 0.3125mol\,{N_2}(x + 0.5z)$
$\left\{ \begin{gathered} x + y + z = 1 \hfill \\ x + 0.5z + 1.5z + y = 1.25 \hfill \\ x + 0.5z = 0.3125 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} x = 0.1875 \hfill \\ y = 0.5625 \hfill \\ z = 0.25 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} \% {N_2}:\,18.75\% \hfill \\ \% {H_2}:\,56.25\% \hfill \\ \% N{H_3}:\,25\% \hfill \\ \end{gathered} \right.$
