`a.`
`Fe+2HCl->FeCl_2+H_2↑`
`n_{Fe}=28/56=0,5(mol)`
`n_{H_2}=n_{Fe}=0,5(mol)`
`V_{H_2}=0,5.22,4=11,2(l)`
`b.`
`n_{HCl}=2n_{Fe}=1(mol)`
`V_{ddHCl}=1/2=0,5(l)`
`c.`
`V_{ddspư}=V_{ddHCl}=0,5(l)`
`n_{FeCl_2}=n_{Fe}=0,5(mol)`
`C_{M_{ddspư}}=(0,5)/(0,5)=1(M)`
`\text{___________________________________}`
Đáp án:
`a.`
`V_{H_2}=11,2(l)`
`b.`
`V_{ddHCl}=0,5(l)`
`c.`
`C_{M_{ddspư}}=1(M)`