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Lephuong
2 năm trước
Để $10x^{n-5}y^{3}$ chia hết cho $x^{6}y^{n-8}$ thì số nguyên n phải thỏa mãn điều kiện A.n=11 B.n>11 C.n $\leq$ 11 D.n $\geq$ 11
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