`b) | 2x - 3| = 5,4`
`=>`\(\left[ \begin{array}{l}2x-3=5,4\\2x-3=-5,4\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}2x=5,4+3\\2x=-5,4+3\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}2x=8,4\\2x=-2,4\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=8,4 : 2\\x=-2,4 : 2\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=4,2\\x=-1,2\end{array} \right.\)
Vậy `x \in { 4,2 ; -1,2}`
`#caty09`
