Với các số thực dương \(x,\,\,y\) tùy ý. Đặt \({\log _2}x = \alpha ,\,\,{\log _2} = \beta .\) Tìm mệnh đề đúng.
A.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = 9\left( {\dfrac{\alpha }{3} - \beta } \right)\)
B.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = \dfrac{\alpha }{3} + \beta \)
C.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = \dfrac{\alpha }{3} - \beta \)
D.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = 9\left( {\dfrac{\alpha }{3} + \beta } \right)\)
A.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = 9\left( {\dfrac{\alpha }{3} - \beta } \right)\)
B.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = \dfrac{\alpha }{3} + \beta \)
C.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = \dfrac{\alpha }{3} - \beta \)
D.\({\log _8}{\left( {\dfrac{{\sqrt[3]{x}}}{y}} \right)^3} = 9\left( {\dfrac{\alpha }{3} + \beta } \right)\)
Loga
Hóa Học lớp 12
