$$\eqalign{
& {{MQ} \over {AH}} = {{BM} \over {BH}} \Leftrightarrow {{MQ} \over {{{a\sqrt 3 } \over 2}}} = {x \over {{a \over 2}}} \Leftrightarrow MQ = x\sqrt 3 = NP \cr
& {{PQ} \over {BC}} = {{AQ} \over {AB}} = {{MH} \over {BH}} \Leftrightarrow {{PQ} \over a} = {{{a \over 2} - x} \over {{a \over 2}}} \cr
& \Leftrightarrow PQ = a - 2x \cr
& \Rightarrow {S_{MNPQ}} = PQ.QM = \left( {a - 2x} \right).x\sqrt 3 \cr
& = - \sqrt 3 \left( {2{x^2} - ax} \right) \cr
& Xet\,\,f\left( x \right) = 2{x^2} - ax \cr
& f'\left( x \right) = 4x - a = 0 \Leftrightarrow x = {a \over 4} \cr
& f\left( 0 \right) = 0;\,\,f\left( {{a \over 4}} \right) = - {{{a^2}} \over 8};\,\,f\left( {{a \over 2}} \right) = 0 \cr
& \Rightarrow {\mathop{\rm minf}\nolimits} \left( x \right) = - {{{a^2}} \over 8} \Rightarrow {S_{MNPQ\,\,\max }} = {{{a^2}\sqrt 3 } \over 8} \cr} $$
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