Giải thích các bước giải:
$(3.\dfrac{x}{5}-\dfrac{1}{3})^2=(\dfrac x5+\dfrac 23)^2$
$\to (3.\dfrac{x}{5}-\dfrac{1}{3})^2-(\dfrac x5+\dfrac 23)^2=0$
$\to (\dfrac{3x}{5}-\dfrac 13-\dfrac x5-\dfrac 23)(\dfrac{3x}{5}-\dfrac 13+\dfrac x5+\dfrac 23)=0$
$\to (\dfrac{2x}{5}-1)(\dfrac{4x}{5}+\dfrac 13)=0$
$\to \dfrac{2x}5-1=0\to x=\dfrac 52$
Hoặc $\dfrac{4x}{5}+\dfrac 13=0\to x=-\dfrac{5}{12}$