Tìm họ nguyên hàm của hàm số \(y = {x^2} - {3^x} + \frac{1}{x}.\)
A.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} - \ln \left| x \right| + C,\,\,\,C \in \mathbb{R}.\)
B.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} + \ln \left| x \right| + C,\,\,\,C \in \mathbb{R}.\)
C.\(\frac{{{x^3}}}{3} - {3^x} + \frac{1}{{{x^2}}} + C,\,\,\,C \in \mathbb{R}.\)
D.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} - \frac{1}{{{x^2}}} + C,\,\,\,C \in \mathbb{R}.\)
A.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} - \ln \left| x \right| + C,\,\,\,C \in \mathbb{R}.\)
B.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} + \ln \left| x \right| + C,\,\,\,C \in \mathbb{R}.\)
C.\(\frac{{{x^3}}}{3} - {3^x} + \frac{1}{{{x^2}}} + C,\,\,\,C \in \mathbb{R}.\)
D.\(\frac{{{x^3}}}{3} - \frac{{{3^x}}}{{\ln 3}} - \frac{1}{{{x^2}}} + C,\,\,\,C \in \mathbb{R}.\)
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