à nhầm chưa đọc kĩ đề hì hì:P
\(x^2+3^y=26\)
\(x^2\ge0\)
\(3^y\ge0\)
\(\Rightarrow0\le x^2;3^y\le26\)
Xét:
\(3^y< 26\Leftrightarrow y=\left\{0;1;2\right\}\)
\(y=0\Rightarrow3^y=1\Rightarrow x^2=25\Rightarrow x=5\left(TM\right)\)
\(y=1\Rightarrow3^y=3\Rightarrow x^2=23\Rightarrow x=\sqrt{23}\left(TM\right)\)
\(y=2\Rightarrow3^y=9\Rightarrow x^2=17\Rightarrow x=\sqrt{17}\left(TM\right)\)
