Giải thích các bước giải:
a,(2x +1)( y-3)=5
Ta có : \(5 = 1 \times 5 = 5 \times 1\)
Th1 : \(\left\{ \begin{array}{l}2x + 1 = 5\\y - 3 = 1\end{array} \right. \Rightarrow \left\{ \begin{array}{l}x = 2\\y = 4\end{array} \right.\,\,\,\left( {TM} \right)\)
Th2 : \(\left\{ \begin{array}{l}2x + 1 = 1\\y - 3 = 5\end{array} \right. \Rightarrow \left\{ \begin{array}{l}x = 0\\y = 8\end{array} \right.\,\,\left( {TM} \right)\)
b, (3x -2)(2y-3)=1
\( \Leftrightarrow \left\{ \begin{array}{l}3x - 2 = 1\\2y - 3 = 1\end{array} \right. \Rightarrow \left\{ \begin{array}{l}x = 1\\y = 2\end{array} \right.\)
