Đáp án đúng: B
Giải chi tiết:Đặt số mol KMnO4 = KClO3 = NaNO3 = KNO3 = 1 (mol)
PTHH:
\(\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,2KMn{O_4}\buildrel {{t^0}} \over \longrightarrow {K_2}Mn{O_4} + Mn{O_2} + {O_2} \cr & (mol)\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to 0,5 \cr} \)
\(\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,2KCl{O_3}\buildrel {{t^0}} \over \longrightarrow 2KCl + 3{O_2} \cr & (mol)\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to 1,5 \cr} \)
\(\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,2NaN{O_3}\buildrel {{t^0}} \over \longrightarrow 2NaN{O_2} + {O_2} \cr & (mol)\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to \,\,0,5 \cr} \)
\(\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,2KN{O_3}\buildrel {{t^0}} \over \longrightarrow 2KN{O_2} + {O_2} \cr & (mol)\,\,\,\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \to \,\,0,5 \cr} \)
Ta thấy số mol O2 sinh ra từ KClO3 = 1,5 mol lớn nhất. Do vậy cùng số mol KClO3 điều chế được lượng O2 nhiều nhất
Đáp án B