Choose the best answer for the following sentence:
Teacher: “You think that you came without __________ ?”
Nam: “I’m sorry because I didn’t ask for your permission”
A. anybody see 
B. being seen 
C. anybody sees 
D. been seen

Choose the word that has the underlined part pronounced differently from the rest:
great                         leak                      eight                   break
A. great                         
B. leak                      
C. eight                   
D. break

Choose a word that has different stress pattern:
provide                     listen                           receive                    believe
A. provide                     
B. listen                           
C. receive                    
D. believe

Diện tích hình phẳng giới hạn bởi các đường y = x – 1 +$\displaystyle \frac{1}{x}$lnx, y = x – 1, x = e là :
A. $\displaystyle \frac{1}{2}$.
B. $\displaystyle \frac{1}{3}$.
C. $\displaystyle \frac{1}{8}$.
D. $\displaystyle \frac{2}{3}$.

Tích phân  $\displaystyle I=\int\limits_{1}^{2}{\frac{\ln x}{{{x}^{2}}}dx}$ bằng
A. $\displaystyle \frac{1}{2}\left( 1+\ln 2 \right)$.
B. $\displaystyle \frac{1}{2}\left( 1-\ln 2 \right)$.
C. $\displaystyle \frac{1}{2}\left( \ln 2-1 \right)$.
D. $\displaystyle \frac{1}{4}\left( 1+\ln 2 \right)$.

Choose the best answer for the following sentence:
Ann's mother __________ when she came home late.
A. worry               
B. worrying                   
C. worried               
D. to be worried

Tích phân $I=\int\limits_{0}^{\pi }{(x+2)cos2xdx}$ bằng
A. $0.$
B. $-\frac{1}{4}.$
C. $\frac{1}{2}.$
D. $\frac{1}{4}.$

Tích phân $I=\int\limits_{0}^{\frac{1}{\sqrt{3}}}{\frac{{{x}^{8}}}{{{({{x}^{4}}-1)}^{2}}}dx}$ bằng
A. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-1.$ 
B. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}.$ 
C. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-12.$ 
D. $\frac{1}{\sqrt{3}}+\frac{1}{4}\ln \frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\pi }{12}-2.$

Tích phân $I=\int\limits_{0}^{\frac{\pi }{4}}{\frac{\cos x}{{{(\sin x+\cos x)}^{3}}}dx}$ có giá trị bằng
A. $\frac{3}{8}.$
B. $-\frac{3}{8}.$
C. $\frac{8}{3}.$
D. $-\frac{8}{3}.$

Cho tích phân $I=\int\limits_{0}^{\frac{\pi }{4}}{(1+\frac{1}{{{\cos }^{2}}x})dx}=a.\pi +b.$ Khi đó tổng a+2b bằng
A. $\frac{9}{2}.$
B. $9.$
C. $\frac{9}{4}.$
D. $\frac{9}{8}.$