1) x + 5x2 = 0
=>x(1+5x) = 0
=>\(\left[\begin{array}{} x=0\\ 1+5x=0 \end{array} \right.\)
=>\(\left[\begin{array}{} x=0\\ x=\dfrac{-1}{5} \end{array} \right .\)
Vậy =-.
2)x+1 = (x+1)2
\(\Rightarrow\) (x+1) - (x+1)2 = 0
\(\Rightarrow\) (x+1)(1- x - 1) = 0
\(\Rightarrow\) -x(x+1) = 0
\(\Rightarrow\)\(\left[\begin{array}{} -x=0\\ x+1 = 0 \end{array} \right.\)
\(\Rightarrow\)\(\left[\begin{array}{} x = 0\\ x = -1 \end{array} \right.\)
Vậy =-...
3) x3 + x = 0
\(\Rightarrow\)x(x2 + 1) = 0
\(\Rightarrow\)\(\left[\begin{array}{} x = 0\\ x^{2} + 1 = 0 \end{array} \right. \)
\(\Rightarrow\)\(\left[\begin{array}{} x = 0\\ x \in \phi \end{array} \right.\)
\(\Rightarrow\) x = 0
Vậy =-
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