Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
ĐK:x \ne - 1;x \ne 2\\
Bpt \to \left[ \begin{array}{l}
\frac{{2x - 1}}{{\left( {x + 1} \right)\left( {x - 2} \right)}} \le \frac{1}{2}\\
\frac{{2x - 1}}{{\left( {x + 1} \right)\left( {x - 2} \right)}} \ge - \frac{1}{2}
\end{array} \right.\\
\to \left[ \begin{array}{l}
\frac{{4x - 2 - {x^2} + x + 2}}{{2\left( {x + 1} \right)\left( {x - 2} \right)}} \le 0\\
\frac{{4x - 2 + {x^2} - x - 2}}{{2\left( {x + 1} \right)\left( {x - 2} \right)}} \ge 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
\frac{{x\left( {x - 5} \right)}}{{2\left( {x + 1} \right)\left( {x - 2} \right)}} \le 0\\
\frac{{\left( {x - 1} \right)\left( {x + 4} \right)}}{{2\left( {x + 1} \right)\left( {x - 2} \right)}} \ge 0
\end{array} \right.
\end{array}\)
BXD: ( ảnh )
KL (ảnh)
