Đáp án:
c) $ + \infty $
d) $ + \infty $
Giải thích các bước giải:
$\begin{array}{l}
c)\lim \left( {{{11}^n} - {3^{2n}}} \right) = \lim \left( {{{11}^n} - {9^n}} \right)\\
= \lim \left[ {{{11}^n}\left( {1 - {{\left( {\frac{9}{{11}}} \right)}^n}} \right)} \right] = + \infty \\
\left( {vi\,\lim {{11}^n} = + \infty ,\lim {{\left( {\frac{9}{{11}}} \right)}^n} = 0} \right)\\
d)\lim \left( {{{\left( {\frac{3}{4}} \right)}^n} + {{\left( {\frac{7}{5}} \right)}^n}} \right) = + \infty \\
\left( {vi\,\lim {{\left( {\frac{3}{4}} \right)}^n} = 0,\lim {{\left( {\frac{7}{5}} \right)}^n} = + \infty } \right)
\end{array}$
