a ) 11 - ( - 52 + 2 . x ) = 97
⇒-52+2x=-86
⇒2x=-34
⇒x=-17
b ) ( x + 7 ) : 3 - 14 = - 29
⇒(x+7):3=-15
⇒x+7=-5
⇒x=-12
c ) ( - 33 + 42 ) . x² = 89 - ( - 136 )
⇒(-33+42).x²=225
⇒9.x²=225
⇒x²=25
⇒x=±5
d ) xy - 2x + y = 13
⇒x(y-2)=13-y
Nếu y-2=0⇒y=2⇒0x=11 (loại)
Chia 2 vế cho y-2$\neq$0
Ta có: x=$\frac{13-y}{y-2}$ 
⇒x=$-1+\frac{11}{y-2}$ 
⇒y-2∈Ư(11)={±1;±11}
y-2=1⇒y=3⇒x=10 (tm)
y-2=-1⇒y=1⇒x=-12 (tm)
y-2=11⇒y=13⇒x=0 (tm)
y-2=-11⇒y=-9⇒x=-2 (tm)
Vậy (x,y)∈{(10;3);(-12;3);(0;13);(-2;-9)}